2. Umass ip address: 128.119.245.12, port: 80
4. The TCP syn has a value of 0, but what identifies it as a syn segment is the value "1 syn:set"
5. The ackknowlegement number is 1. The umass website determines this value because it is acknlowleging the the syn value.
6. The sequence number is 1.
7. POST: 5, 7, 11, 13, 16, 17 Sequence numbers: 1, 249, 725, 1388, 1709, 2196
ACKS: 8, 10, 12, 14, 19, 20
8. POST 5: 248 POST 7, 11, 17, 19, 8: 724
9. The minimum window size is 16425. This does not throttle the buffer because the window size is so large and it will keep growing.
10. No, because one can see using the time graph that the packet rate the time it takes and sequence numbers are increasing proportionally.
11. The reciever typically recieves 16425 bytes of data per packet.
12. 16424/ .82977= 19.79 kb/sec
13. The slow start begins at the start of the connection and ends shortly after. In the text examples, too much data is being sent on purpose so naturally the network will be congested quickly. In this example it is being sent in relatively small amounts so there is no congestion.
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